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[U Q. 17. Prove that . 2N 8+sec8-1= sec + tan ©.tan © —-sec9 -1e

Answer»

LHS:- tan theta + sec theta - (sec²theta - tan² theta /tan theta - sec theta + 1 =( tan theta + sec theta)(1- sec theta + tan theta )/tan theta +1 - sec theta =tan theta +sec theta =sin theta / cos theta + 1/cos theta = 1+ sin theta / cos theta ⁼sec theta+ tan thetaLHS = RHS Hence proved

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