1.

U1 , q, w, U2 are given. U is internal energy, q is absorbed heat, w is work done and U2 is final energy. (a) Derive an equation for ∆U. (b) Give the equation for w. (c) Calculate the change in internal energy of a system which absorbs 200 J of heat and 315 J of work is done by the system.

Answer»

(a) U2 = U1 + q +w 

U2 – U1 = q + w 

or ∆U = q + w 

(b) w= -p∆V

(c) q = 200J 

w = -315J 

∆U = ? 

∆U = q + w 

= 200 + {315} 

= 200 - 315 = -115J



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