Saved Bookmarks
| 1. |
U1 , q, w, U2 are given. U is internal energy, q is absorbed heat, w is work done and U2 is final energy. (a) Derive an equation for ∆U. (b) Give the equation for w. (c) Calculate the change in internal energy of a system which absorbs 200 J of heat and 315 J of work is done by the system. |
|
Answer» (a) U2 = U1 + q +w U2 – U1 = q + w or ∆U = q + w (b) w= -p∆V (c) q = 200J w = -315J ∆U = ? ∆U = q + w = 200 + {315} = 200 - 315 = -115J |
|