ue is UT'GST instead of SGST.)Find four consecutive terms in an A.P. w

1.	ue is UT'GST instead of SGST.)Find four consecutive terms in an A.P. whose sum is 88 and the sum of the 1st and the3rd terms is 40ke the following questions: (An Qe
Answer» Let four consecutive terms are a - 3d , a - d , a + d , a + 3d , where a and d is real numbers. According to question, sum of all four terms = 88(a - 3d) + (a - d) + (a + d) + (a + 3d) = 884a = 88 a = 22 ......(1) again, sum of 1st and 3rd term is 40e.g., (a - 3d) + (a + d) = 402a - 2d = 40a - d = 20 from equation (1), 22 - d = 20d = 2 hence, a = 22 and d = 2 then, a - 3d = 22 - 3 × 2 = 22 - 6 = 16 a - d = 22 - 2 = 20a + d = 22 + 2 = 24 a + 3d = 22 + 3× 2 = 22 + 6 = 28 therefore, four consecutive term in an A.P are 16, 20, 24, 28

ue is UT'GST instead of SGST.)Find four consecutive terms in an A.P. whose sum is 88 and the sum of the 1st and the3rd terms is 40ke the following questions: (An Qe

Answer»

Let four consecutive terms are a - 3d , a - d , a + d , a + 3d , where a and d is real numbers.

According to question, sum of all four terms = 88(a - 3d) + (a - d) + (a + d) + (a + 3d) = 884a = 88 a = 22 ......(1)

again, sum of 1st and 3rd term is 40e.g., (a - 3d) + (a + d) = 402a - 2d = 40a - d = 20 from equation (1), 22 - d = 20d = 2

hence, a = 22 and d = 2 then, a - 3d = 22 - 3 × 2 = 22 - 6 = 16 a - d = 22 - 2 = 20a + d = 22 + 2 = 24 a + 3d = 22 + 3× 2 = 22 + 6 = 28

therefore, four consecutive term in an A.P are 16, 20, 24, 28