InterviewSolution
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InterviewSolution
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umber of atoms presentin 1,0 cm3 of solid glucose (density 0.8g/cms8 1021(B) 6.42x 10(C) 2.68 x10 |
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Answer» The mass of glucose can be found out by M=V*Density. = 1*0.8 = 0.8 gms but the molecular mass of glucose is 180gm. so no. of moles = 0.8/180 = 4.4 × 10^{-3} and in 1 mole , no. of atoms = 6.02*10^{23} so in 4.4 × 10^{-3} , no. of atoms is = 4.4 × 10^{-3} x 6.02*10^{23}^{21} = 2.68x10^{21}. |
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