Under an adiabatic process, the volume of an ideal gas gets doubled. Consequently, the mean collision time between the gas molecules changes from tau_(1) " to" tau_(2). If (C_(P))/(C_(V))= gamma for this gas, then a good estimate for (tau_(2))/(tau_(1)) is given by

Under an adiabatic process, the volume of an ideal gas gets doubled. C

1.	Under an adiabatic process, the volume of an ideal gas gets doubled. Consequently, the mean collision time between the gas molecules changes from tau_(1) " to" tau_(2). If (C_(P))/(C_(V))= gamma for this gas, then a good estimate for (tau_(2))/(tau_(1)) is given by
Answer» `(1)/(2)` 2 `((1)/(2))^(gamma)` `((1)/(2))^((gamma)/(2) +1)` SOLUTION :Relaxaation time `TAU PROP (V)/(sqrtT) and T prop (1)/(V^(gamma-1))` `:. tau prop V^(1 + (gamma-1)/(2))` `:. tau= V^((1 + gamma)/(2))` `:. (tau_(1))/(tau_(i)) = ((2V)/(V))^((1 + gamma)/(2)) = (2)^((1 + gamma)/(2))`