1.

Under identical conditions of pressure and temperature

Answer»

`(r_(H_2))/(r_(O_2)) = 4`
`(r_(H_2))/(r_(CH_4)) = 2.83`
`(r_(He))/(r_(CH_4)) = 2`
`(r_(He))/(r_(SO_2)) = 4`

SOLUTION :`(gamma_(H_2))/(gamma_(O_2)) = SQRT((32)/(2)) = 4 , (gamma_(H_2))/(gamma_(CH_4)) = sqrt(16/2) = sqrt(8) = 2.83`.
`(gamma_(He))/(gamma_(CH_4)) = sqrt((16)/(4)) = 2 , (gamma_(He))/(gamma_(SO_2)) = sqrt((64)/4) = 4`.


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