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Under isothermal conditions, a gas at 300 K expands from 0.1 L to 0.25 L against a constant external pressure of 2 bar.The work done by the gas is [ Given that 1 L bar = 100 J] |
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Answer» Solution :`w = -p_(ext)(V_(2) - V_(1))` `p_(ext)` = 2 BAR, `V_(1) = 0.1 L, V_(2) = 0.25 L` w = -2(0.25 - 0.1) `= -2 xx 0.15 = -0.30` bar L ` = -0.30 xx 100 = -30` J |
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