1.

Under isothermal conditions, a gas at 300 K expands from 0.1 L to 0.25 L against a constant external pressure of 2 bar.The work done by the gas is [ Given that 1 L bar = 100 J]

Answer»

<P>30 J
`-30 J`
5 kJ
25 J

Solution :`w = -p_(ext)(V_(2) - V_(1))`
`p_(ext)` = 2 BAR, `V_(1) = 0.1 L, V_(2) = 0.25 L`
w = -2(0.25 - 0.1)
`= -2 xx 0.15 = -0.30` bar L
` = -0.30 xx 100 = -30` J


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