Under the action of force P, the constant acceleration of block B is 3 ms^(-2) to the right. At the instant when the velocity of B is 2 ms^(-1) to the right, determine the velocity of B relative to A, the acceleration of B relative to A and the absolute velocity of point C of the cable.

Under the action of force P, the constant acceleration of block B is 3

1.	Under the action of force P, the constant acceleration of block B is 3 ms^(-2) to the right. At the instant when the velocity of B is 2 ms^(-1) to the right, determine the velocity of B relative to A, the acceleration of B relative to A and the absolute velocity of point C of the cable.
Answer» 2 1 3 4 Solution :`-3TV_(B)+4TV_(A)=0, V_(A)=3/4V_(B)=3/2` `(V_(B)+V_(C))/2=V_(A),V_(C)=2V_(A)-V_(B),V_(C)=3-2=1`