1.

Under the same reaction conditions, intial concentration of 1.386 mol dm^(-1) of a substance becomes half in 40 s and 20 s through first order and zero order kinetics respectively. Ratio ((k_1)/(k_0)) of the rate constants for first order (k_1) and zero order (k_0) of the reaction is

Answer»

`0.5 MOL^(-1) dm^(-3)`
`1.5 mol dm^(-3)`
`1.5 mol dm^(-3)`
`2.0 mol^(-1) dm^(-1)`

Solution :First ORDER kinetics,
`k_1=(0.693)/(t_1//2) = 0.693/40 s^(-1)`
Zero order kinectics,
`k_1 = C_0/(2t_1//2) = 1.386/(2xx 20)`
HENCE, `k_1/k_0 = 0.693/1.386 = 0.5`


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