`underset(1 L solution)(Ag|Ag^(o+)(1M))||underset(1 L solution)(Ag^(o+)||Ag)` `0.5F` electricity in the `LHS(` anode `)` and `1F` of electricity in the `RHS(` cathode`)` is first passed making them independent electrolytic cells at `298K`. `EMF` of the cell after electrolysis will beA. IncreasedB. DecreasedC. No changeD. Time is also required

`underset(1 L solution)(Ag|Ag^(o+)(1M))||underset(1 L solution)(Ag^(o+

1.	`underset(1 L solution)(Ag\|Ag^(o+)(1M))\|\|underset(1 L solution)(Ag^(o+)\|\|Ag)` `0.5F` electricity in the `LHS(` anode `)` and `1F` of electricity in the `RHS(` cathode`)` is first passed making them independent electrolytic cells at `298K`. `EMF` of the cell after electrolysis will beA. IncreasedB. DecreasedC. No changeD. Time is also required
Answer» Correct Answer - c `E=E^(c-)+(0.0591)/(1)log.([Ag^(o+)]_(R))/([Ag^(o+)]_(L))` `=0+0.0591log 2=0.0591xx0.301V` After current is passed `[Ag^(o+)]_(R)=1M` `[Ag^(o+)]_(L)=0.5M` Hence, no change in `EMF`.

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