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`underset("(B) white fumes")underset(darr)(MCl_(4)"(colourless liquid) M = transition metal moist air") overset(Zn+H_(2)O)(rarr) underset((A))("Purple coloured compound")` Identify (A), (B) and `MCl_(4)` . Also explain colour differnece between `MCl_(4)` and (A) . |
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Answer» `MCl_(4) = TiCl_(4)` ( colourless, diamagnetic, covalent fuming liquid ) `TiCl_(4)(aq) underset(Delta"(Reduction)") overset(Zn) (rarr)TiCl_(3)overset(H_(2)O) (rarr) underset("Purple coloured(A))")([Ti(H_(2)O)_(6)]Cl_(3))` `TiCl_(4)+ H_(2)O rarrTiOCl_(2) + underset("White fumes (B)") (2HCl)` Hence, `A=[Ti(H_(2)O)_(6)] Cl_(3) ,B = HCl,MCl_(4) = TiCl_(4)` Coloure difference. `TiCl_(4)` is colourless because Ti(IV) has empty d-subhsell. Hence, no d-d transition is possible, Ti(III) has `d^(1)` configuration . Hence, Ti(III) is coloured due to d-d transition . `Ti^(3+)` absorbs greenish yellow component of white light . The complementary coloure is purple. Hence, aqueous solution containing `T^(3+)` ions is purple. |
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