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`underset(("bot"))(Cu+conc.HNO_(3))toCu(NO_(3))_(2)+X` (oxide of nitrogen) then X is:A. `N_(2)O`B. `NO_(2)`C. `NO`D. `N_(2)O_(3)` |
Answer» Correct Answer - B `2 conc. HNO_(3) to 2H_(2)O+2NO_(2)+[O]` `Cu+2HNO_(3) to Cu(NO_(3))_(2)+2[H]` `2[H]+[O]to2H_(2)O` |
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