1.

underset("having smell")underset("White fumes")(B)overset("Moist air")larrunderset("element colourless")underset("M=Transition")(MCI_(4))overset(Zn)rarrunderset("colour")underset("Purple")(A) Identifythe metal M and hence MCl_(4). Explainthedifference incolour of MCl_(4) and A.

Answer»

Solution :`underset("having SMELL")underset("White FUMES")(B)overset("Moist air")larr underset("element, colourless")underset(M=("Transition"))(MCI_(4))overset(Zn)RARR underset("COLOUR")underset("Purple")(A)`
`M = Ti, MCI_(4) + TiCI+_(4)`
`A = [Ti(H_(2)O)_(6)]^(3+) B = TiO_(2)`
`Ti(IV) ` ion constains no d-element , so it is colourless .
`Ti(III) ` ion constains one d-element , so it is coloured .


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