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Unit 5 ka 5.6 |
| Answer» 2Al(2*27g)+2NaOH+2H2O→2NaAlO2+3H2(3*22400ml at STP. H2O produced at STP from 0.15g Al=3*22400*0.15/54 ml=186.7ml. P1V1/T1=P2V2/T2. 1atm*186.7ml/273K=0.987atm x V2/293k. V2=203ml. answer | |