Upon mixing 45.0 ml of 0.25 M lead nitrate solution with25 ml of 0.10 – InterviewSolution

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1.	Upon mixing 45.0 ml of 0.25 M lead nitrate solution with25 ml of 0.10 M chromic sulphate solution , precipitation of lead sulphate takes place . How many moles of lead sulphate are formed ? Also calculate the concentration of the species left behind in final Solution : Assume that lead sulphate is completely insoluble.
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