1.

Urine has a pH of 6.0 . If a patient eliminates 1300 ml of urine per day, how many gram equivalents of the acid he eliminates per day ?

Answer»


Solution :pH = 6.0means `[H_(3)O^(+)]=10^(-6)M, ` i.e., [Acid] `= 10^(-6)M = 10^(-6)N`
Thus, 1000 ml of the urine contain acid `=10^(-6)G` EQ.
`:.` 1300 ml of the urine will contain acid `=1.3 XX 10^(-6) ` g eq.


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