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URUL UCetteQ.21(ABS.CASAn Organic compound on analysis gave the followius, percentage compositionC: 57.8%, H=3.6% and the rest is oxygen. The vapour density of the compound was found to beFind the molecular formula of the compound.(Aus.COM |
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Answer» Compositionof C = 57.8%Composition of H = 3.6%Total composition of organic compound = 100%Composition of oxygen = 100 - (57.8 + 3.6) = 38.6% Element composition Atomic mass Ratio of atoms Simplest ratio C 57.8% 12 57.8/12 = 4.82 4.82/2.41 = 2 H 3.6% 1 3.6/1 = 3.6 3.6/2.41 = 1 O 38.6% 16 38.6/16 = 2.41 2.41/2.41 = 1 Therefore the empirical formula of the compound = C2HO Molecular weight = 2 * vapour density = 2*83 = 166 Emperical formula weight = 24+1+16 = 41 n = Molecular weight/Emperical weightn = 166/41n = 4 (nearly) Molecular formula = 4(C2HO) = C8H4O4 |
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