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Use distributive law (26)×72 +(26)×28 |
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Answer» he Distributive Law of Multiplication [(a×b)+(a×C)=a(b+c)] Let, a = -26, b = 72, c = 28 Then, =(−26)×(72)+(−26)×(28) The above equation can be WRITTEN as, ={(−26)×(72+28)} .[∵(a×b)+(a×c)=a×(b+c)] ={(−26)×(100)} . [∵(+×−=+)] =-2600 |
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