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Use Hund's rule to derive the electronic configuration of Ca^(3+) ion, and calculate its magnetic moment on the basis of 'spin-only' formula. |
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Answer» Solution :Ceriumhas the configuration : `[Xe]4F^(1)5d^(1)6s^(2)` Configuration of `Ce^(3+)` may be written as : `[Xe]4f^(1)`, i.e., there is only one unpaired electron, i.e., n = 1. Hence, MAGNETIC moment is given by : `mu=sqrt(n(n+2))=sqrt(1(1+2))=sqrt(3)=1.73` BM. |
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