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Use the assumptions of the previous question. An object weighed by a spring balance at the equator gives the same reading as a reading taken at a depth d below the earth’s surface at a pole (d << R). The value of d is(a) ω2R2 / g(b) ω2R2 / 2g(c) 2ω2R2 / g(d) √Rg / ω |
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Answer» Correct Answer is: (a) ω2R2 / g |
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