Use the following data tocalculate Delta_("lattice") H^(c-) for NaBr. Delta_("sub") H^(c-) for sodium metal =108.4 kJ mol^(-1) Ioniztion enthalpy ofsodium = 496kJ mol^(-1) Electron gain enthalpy of bromine = - 325 kJ mol^(-1) Bond dissociation enthalpy of bromine =192kJ mol^(-1) Delta_(f)H^(c-)for NaBr(s) = - 360.1 kJ mol^(-1)

Use the following data tocalculate Delta_("lattice") H^(c-) for NaBr.

1.	Use the following data tocalculate Delta_("lattice") H^(c-) for NaBr. Delta_("sub") H^(c-) for sodium metal =108.4 kJ mol^(-1) Ioniztion enthalpy ofsodium = 496kJ mol^(-1) Electron gain enthalpy of bromine = - 325 kJ mol^(-1) Bond dissociation enthalpy of bromine =192kJ mol^(-1) Delta_(f)H^(c-)for NaBr(s) = - 360.1 kJ mol^(-1)
Answer» Solution :Proceedas in CALCULATION of LATTICE enthalpy for NaCl on page . We GET `Delta_("lattice") H^(@) ( NaBr)= - 360 .1 kJ MOL^(-1)`