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Use the formula v = √{γp/ρ} to explain why the speed of sound in air(i) is independent of pressure,(ii) increases with temperature,(iii) increases with humidity. |
Answer» We are given that, v = √{γp/ρ} We know that pV = nRT ⇒ pV = m/M RT where m is the total mass and M is the molecular mass of the gas. p = m/M.RT/V = ρRT/M ⇒ p/ρ = RT/M (a) For gas at constant temperature, p/ρ = constant As p increases, ρ also increases and vice versa. This implies that v = √{γp/ρ} = const. i.e., velocity is independent of pressure of the gas. (a) Since p/ρ = RT/M Therefore, v = √{γp/ρ} = √{γRT/M} Clearly v α √T, i.e., Speed of sound in air increases with increase in temperature. (c) Increase in humidity decreases the effective density of air. Therefore, the velocity (v x 1/√ρ) increases. |
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