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Usha swims in a `90 m` long pool. She covers `180 m` in one minute by swimming from one end to the other and back along the same length path. Find the average speed and average speed and average velocity of Usha. |
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Answer» Correct Answer - `3 ms^(-1)` ; zero Here , total distance travelled , ` s = 180 m` , time taken , `t = 1 min. = 60s` Average speed `= (s)/(t) = ( 180)/( 60) = 3 m//s` In swimming from one end to the other and back along the same straight path , displacement `= 0`. Average velocity `= ("displacement")/("time") = zero` |
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