Using a directrix of y = -2 and a focus of (2, 6), what quadratic function is created? f(x) = -1/8(x - 2)2 - 2 f(x) = 1/16(x - 2)2 + 2 f(x) = 1/8(x - 2)2 - 2 f(x) = -1/16(x + 2)2 - 2

Using a directrix of y = -2 and a focus of (2, 6), what quadratic func

1.	Using a directrix of y = -2 and a focus of (2, 6), what quadratic function is created? f(x) = -1/8(x - 2)2 - 2 f(x) = 1/16(x - 2)2 + 2 f(x) = 1/8(x - 2)2 - 2 f(x) = -1/16(x + 2)2 - 2
Answer» Using a directrix of y = -2 and a focus of (2, 6), what quadratic function is created? Solution: