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Using calculas method show that v²-u²=2as |
| Answer» \tEquation For Position - Velocity Relation:From the velocity-time graph, the distance s travelled by the object in time t, moving under uniform acceleration a is given by the area enclosed within the trapezium OABC under the graph. That is,s = area of the trapezium OABC = (OA + BC) X OC/2Substituting OA = u, BC = v and OC = t,We gets= (u+v) t/2From the velocity-time relationWe gett= v - u/aWe haves = (v + u) x (v – u)/2aor 2as = v2 – u2 | |