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Using contrapositive method prove that if n2 is an even integer, then n is also an even integers. |
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Answer» Let us assume p: n2 is an even integer. ~p: n is not an even integer q: n is also an even integer ~q=n is not an even integer. Since, in the contrapositive, a conditional statement is logically equivalent to its contrapositive. Therefore, ~q → ~p = If n is not an even integer then n2 is not an even integer. Hence, ~q is true → ~p is true. |
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