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Using dimensional analysis show that 1N//m^(2)=10"dyne"//cm^(2). |
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Answer» Solution :PRESSURE =Force /Area `=[ML^(-1)T^(-2)]n_(2)=n_(1)(M_(1)//M_(2))^(x)(L_(1)//L_(2))^(y)(T_(1)//T_(2))^(z)` From the two equations `x=1,y=-1,z=-2, M_(1)//M_(2)=1kg//g=1000` `L_(1)//L_(2)=100cm//CM=100,T_(1)//T_(2)=1, n_(2)=n_(1)(1000)^(1)(100)^(-1)XX(1)^(-2)=n_(1)xx10` `n_(1)=1, n_(2)=10,n_(1)N//m^(2)=n_(2)` dyne /`cm^(2)` i.e.`1N//m^(2)=10"dyne"//cm^(2)` |
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