1.

Using dimensions method show that the speed of sound in a material medium of modulus of elasticity E and density rho is v prop sqrt(E/(rho))

Answer»

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Solution :`vprop E^(x)rho^(y)`
`v=kE^(x)rho^(y)` ……1 k is a DIMENSIONLESS constant
Dimensions of `E=("Stress")/("Strain")=ML^(-1)T^(-2)`. Strain has no dimensions
Taking the dimensions of equation (1) on both SIDES
`LT^(-1)=[ML^(-1)T^(-2)]^(x)[ML^(-3)]^(y)=M^(x)L^(-x)T^(-2x)M^(y)L^(-3y)`
`M^(0)LT^(-1)=M^(x+y)L^(-x-3y)T^(-2x)`
Equating the dimensios on both sides
of T `-1=-2x,x=1//2`
of M `x+y=0, y=-x-1//2`
Substituting the values of x and y in equation (1) we get
`v=k E^(1//2)p^(-1//2)`
or `v prop sqrt(E/(rho))`


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