1.

Using factor theorem, show that (x – 5) is a factor of the polynomial 2x3 – 5x2 – 28x + 15

Answer»

Let P(x) = 2x3 – 5x2 – 28x + 15 

By factor theorem, (x – 5) is a factor of P(x), if P(5) = 0 

P(5) = 2(5)3 – 5(5)2 – 28(5) + 15 

= 2 x 125 – 5 x 25 – 140 + 15 

= 250 – 125 – 140 + 15 = 265 – 265 = 0 

∴ (x – 5) is a factor of 2x3 – 5x– 28x + 15



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