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Using factor theorem, show that (x – 5) is a factor of the polynomial 2x3 – 5x2 – 28x + 15 |
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Answer» Let P(x) = 2x3 – 5x2 – 28x + 15 By factor theorem, (x – 5) is a factor of P(x), if P(5) = 0 P(5) = 2(5)3 – 5(5)2 – 28(5) + 15 = 2 x 125 – 5 x 25 – 140 + 15 = 250 – 125 – 140 + 15 = 265 – 265 = 0 ∴ (x – 5) is a factor of 2x3 – 5x2 – 28x + 15 |
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