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Using free body diagram show that it is easy to pull an object than to push it |
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Answer» <P> Solution :Whena bodyis pushedat anarbitraryangle `theta` thatvariesfrom `(p " to"(pi )/(2))` . TheappliedforceF canberesolvedintotwocomponentsas Fsin `theta` parallelto the surfaceand F cos `theta` prependicularto the SURFACE. Thetotaldownwardforceactingon thebodymg +F cos `theta` . Itis impliedthat thenormalforceactingon thebodyincrease. sincethereis noaccelerationalongthe verticaldirectionthe normalforce N is given byAs a resultthe maximalstaticfrictionalsoincreasesand thatis EQUAL to `f_(s) ^(MAX)= mu_(s)N_(push)` `-mu_(s ) (mg + F cos theta)` Equationshows thata greaterforceneedstobe appliedto pushthe objectintomotion ![]() Whenan OBJECTIS pulledat anangle `theta` the aplliedforceisresolvedinto twocomponents. The totaldownwardforceacting on theobject is Equation (3)showsthat thenormal forceis less that `N_(push)`Fromequation `(1) ` and (3)weknowthat itis easier to pullan objectthattopushto makeit move. |
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