Using Gibb's free energy change, AG^@ = 57.34 kJ mol^(-1), for the rea – InterviewSolution

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1.	Using Gibb's free energy change, AG^@ = 57.34 kJ mol^(-1), for the reaction, X_2 Y_((s)) hArr2X^+ +Y_((aq)^3)^(2-) calculate the solubility product of X_2 Y in water at 300 K (R=8.3 JK^(-1) Mol^(-1))
Answer» `10^(-10)` `10^(-12)` `10^(-14)` can not CALCULATED from the GIVEN data. Answer :A

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