1.

Using MOT, compare O_2^(+) and O_2^(-) species and choose the incorrect option.

Answer»

`O_(2)^(-)` is less STABLE
Both `O_(2)^(+) and O_(2)^(-)` are paramagnetic
`O_(2)^(+)` have higher BOND orderthan `O_(2)^(-)`
`O_(2)^(+)` is diamagnetic while `O_(2)^(-)`is paramagnetic .

Solution :Molecular orbital configuration of `sigma1s^(2)"*"1s^(2)sigma2s^(2)sigma "*"2s^(2)sigma2p_(z)^(2) pi2p_(X)^(2)= pi2p_(y)^(2) pi "*"2p_(x)^(1)`
Bond order ` = 1/2 (10-5) = 2.5`
Number of unpaired electrons = 1 , HENCE paramagneticc
Molecular orbital configuration of `O_(2)^(-): sigma1s^(2) sigma^("*")sigma 2s^(2)sigma^"*"2s^(2) sigma 2p_(z)^(2)pi2p_(x)^2 = pi2p_(y)^(2) pi"*" 2p_(x)^(2)= pi"*"2p_(y)^(1)`
Bond order`=1/2 (10-7) = 1.5`
Number of unpaired ELECTRON = 1 , henceparamagnetic
Both `O_(2)^(+) and O_(2)^(-) ` are paramagnetic
`O_(2)^(+)` have higherbondorder than `O_(2)^(-)`
`O_(2)^(-)` is less stable .


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