1.

Using Newton's law of gravitation, prove Kepler's III^(rd) law of planetary motion for circular orbits.

Answer»

Solution :PLANET of mass 'm' moves around the Sun of mass 'M' in a circular orbit of radius 'R' with orbital velocity v.
`therefore(mv^2)/(r)=(GMm)/(r^2)`
`v^(2)=(GM)/(r)""...(1)`
But,
Orbital speed `(v)=("circumference")/("period of revolution")=(2pir)/(T)`
Squaring,
`v^(2)=(4pi^(2)r^(2))/(T^2)""...(2)`
Comparing of equations (1) and (2), we get
`(GM)/(r)=(4pi^(2)r^(2))/(T^2)`
In CROSS MULTIPLICATION, `(GMm)/(r^2)`
`T^(2)PROPR^(3)`


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