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Using Raoult's law explain how the total vapour pressure over the solution is related to mole fraction of components in the following solutions.(a) CHCl_(3(l))(b)CH_(2)Cl_(2(l)) |
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Answer» Solution :(i) `CHCl_(3)` : For a binary solution having both components as volatile liquids (viz. `CHCl_(3)` and `CH_(2)Cl_(2)`), the total pressure will be `p=x_(1)p_(1)^(0)+x_(2)p_(2)^(0)` `= p_(1)^(0)+1-x_(2)p_(2)^(0)` `= (p_(1)^(0)-p_(2)^(0))x_(1)+p_(2)^(0)` p = total vapour pressure of the given MIXTURE / binary solution of the given volatile liquids. `p_(1)=` partial vapour presure of component 1 (i.e., `CHCl_(3)`) `p_(2)=` partial vapour pressure of component 2 (i.e., `CH_(2)Cl_(2)`) (ii) `NaCl_((s))`and `H_(2)O_((l))` : For a solutioncontaining non - volatile solute i.e., `NaCl_((s))`and `H_(2)O_((l))`, the Raoult.s LAW is applicable only to vaporisable component (1) i.e., `H_(2)O_((l))` and total vapour pressure is written as `p=p_(1)=x_(1)p_(1)^(0)` where `p_(1)^(0)p_(1)` oreresents the vapour pressure of pure `H_(2)O_((l))` |
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