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Using Slater's rule calculate the effective nuclear charge on a 3p electron in aluminium and chlorine .Explain how these results relate to the atomic radii of the two atoms. |
Answer» Solution :`ubrace(Al^(13) 1s^(2))_((N-2)) ubrace(2s^(2) 2P^(6))_((n-1))ubrace(3s^(2) 3p^(1))_((n))` `:.` EFFECTIVE nuclear change =Z-S=13-9.5 `(Z_(eff))_Al=3.5` Electronic CONFIGURATION of CHLORINE `ubrace(1s^(2))_((n-2)) ubrace(2s^(2) 2p^(6))_((n-1)) ubrace(3s^(2) 3p^(5))_((n))` ![]() `:.` Effective nuclear charge =Z-S=17=10.9 `(Z_(eff))_Cl=6.1` `(Z_(eff))_Clgt(Z_(eff))_Al` and hence `r_(Cl) ltr_(Al)` |
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