1.

Using the calculated emf value of zinc and copper electrode, calculate the emf of the following cell at 25^@C Zn(s)|Zn^(2+)(aq, 1M)|Cu^(2+)(aq, 1M)|Cu(s)

Answer»

Solution :`E_("CELL")^(@) = E_R^@ - E_L^@`
`E_(Zn//Zn^(2+)) = 0.76 V`
`E_(CU^(2+)//Cu) = -0.34V`
`E_("cell")^(@) = 0.76 - (-034)`
`E_("cell")^(@) = +1.1V`.


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