Using the data given below: `E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V E_(Cl_(2)|Cl^(-))^(@)=1.36V` `E_(MnO_(4)^(-)|Mn^(2+))^(@)=1.51V E_(Cr^(3+)|Cr)=-0.74V` Find the most stable oxidised species.A. `Cr^(3+)`B. `MnO_(4)^(-)`C. `Cr_(2)O_(7)^(2-)`D. `Mn^(2+)`

Using the data given below: `E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V E_

1.	Using the data given below: `E_(Cr_(2)O_(7)^(2-)\|Cr^(3+))^(@)=1.33V E_(Cl_(2)\|Cl^(-))^(@)=1.36V` `E_(MnO_(4)^(-)\|Mn^(2+))^(@)=1.51V E_(Cr^(3+)\|Cr)=-0.74V` Find the most stable oxidised species.A. `Cr^(3+)`B. `MnO_(4)^(-)`C. `Cr_(2)O_(7)^(2-)`D. `Mn^(2+)`
Answer» `E_(Cr^(3+)//Cr)^(@)` has most -ve value equal to -0.74 among given four choices. So `Cr^(3+)` is the most stable oxidised species.

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Using the data given below: `E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V E_(Cl_(2)|Cl^(-))^(@)=1.36V` `E_(MnO_(4)^(-)|Mn^(2+))^(@)=1.51V E_(Cr^(3+)|Cr)=-0.74V` Find the most stable oxidised species.A. `Cr^(3+)`B. `MnO_(4)^(-)`C. `Cr_(2)O_(7)^(2-)`D. `Mn^(2+)`

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