1.

Using the data given below find out the strongest reducing agent. E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(Theta)=1.33V,E_(Cl_(2)|Cl^(-))^(Theta)=1.36V E_(MnO_(4)^(-)|Mn^(2+))^(Theta)=1.51V,E_(Cr^(3+)|Cr)^(Theta)=-0.74V

Answer»

`Cl^(-)`
`Cr`
`Cr^(3+)`
`Mn^(2+)`

Solution :The standard reduction ELECTRODE potential of `E_(Cr^(3+)|Cr)^(Theta)=-0.74V` is very LESS value (Highly negative).
So Cr is STRONG reducing agent.
`Cr to Cr^(3+) +3e^(-)`
* Cr EASILY oxidize and hence it is strong reducing in nature. `Mn^(2+) lt Cl^(-) lt Cr^(3+) lt Cr`.


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