1.

Using the data given below find out the strongest reducing agent. E_(Cr_(2)O_(7)^(2-)//Cr^(3+))^(Theta)=1.33V,E_(Cl_(2)//Cl^(-))^(Theta)=1.36V E_(MnO_(4)^(-)//Mn^(2+))^(Theta)=1.51V,E_(Cr^(3+)//Cr)^(Theta)=-0.74V

Answer»

`Cl^(-)`
`CR`
`Cr^(3+)`
`Mn^(2+)`

SOLUTION :Strongest reducing agent is ONE which is oxidized most easiliy, i.e., which has HIGHEST oxidation potential. Given values are REDUCTION potentials. Reversing the sign will give oxidation potentials.thus, `Cr//Cr^(3+)` will have highest oxidation potential (+0.74V). hence, Cr is oxidized most easiliy `(CrtoCr^(3+)+3e^(-))` and, therefore, is the strongest reducing agent.


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