Using the data provided, calculate the bond energy( kJ mol^(-1))of a C-=C bond in C_(2)H_(2).That eneergy is ( take the bond energy ofC-H bond as350 kJ mol^(-1))2C(s) + H_(2)(g) rarr C_(2)H_(2)(g)" " DeltaH = 225 kJ mol^(-1) 2C(s) rarr 2C(g) " " DeltaH = 1410 kJ mol^(-1) H_(2)(g) rarr 2H(g)" " DeltaH = 330 kJ mol^(-1)

Using the data provided, calculate the bond energy( kJ mol^(-1))of a C

1.	Using the data provided, calculate the bond energy( kJ mol^(-1))of a C-=C bond in C_(2)H_(2).That eneergy is ( take the bond energy ofC-H bond as350 kJ mol^(-1))2C(s) + H_(2)(g) rarr C_(2)H_(2)(g)" " DeltaH = 225 kJ mol^(-1) 2C(s) rarr 2C(g) " " DeltaH = 1410 kJ mol^(-1) H_(2)(g) rarr 2H(g)" " DeltaH = 330 kJ mol^(-1)
Answer» 1165 837 875 815 Solution :(i) `2C(s) + H_(2)(g) rarr H-C-= C-H(g), DeltaH=225kJ mol^(-1)` (II) `2C(s) rarr 2C(g) , DeltaH = 1410kJ mol^(-1)` (iii) `H_92)9g)rar 2H(g), DeltaH = 330 KJ mol^(-1)` From eq. (i) `225= [2 xxDelta_(C(s) rarr C(g)) + BE_(H-H)]-[2BE_(C-H)+BE(C-=C)]` or `225=[ 1410 + 330]-[2 xx 350 k+ BE_(C-=C)]` or ` 225=1740- 700- BE_(C-=C)` or`BE_(C-=C) 1040-225 = 815kJ mol^(-1)`