1.

Using the data provided, calculate the multiple bond energy (kJ mol^(-1)) of a C-=C bond in C_(2)H_(2). That energy is (take the bond energy of a C-H bond as 350 kJ mol^(-1))2C(s)+H_(2)(g)rarrC_(2)H_(2)(g)""DeltaH=225 kJ mol^(-1)2C(s)rarr2C(g)""DeltaH=1410kJ mol^(-1)H_(2)(g)rarr2H(g)""DeltaH=330kJ mol^(-1)

Answer»

1165
837
865
815

Solution :
`THEREFORE DeltaH=+1410 + 330 -(350xx2)-epsilon_(C-=C)=+225`
`therefore epsilon_(C-=C)=1740-1700-225=+815 kJ//mol`.


Discussion

No Comment Found

Related InterviewSolutions