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Using the date in the preceding problem, calculate the equilibrium constant of the reaction at `25^(@)C` `Zn +Cu^(++) hArr Zn^(++) +Cu, K ([Zn^(2+)])/([Cu^(2+)])`A. `8.314 xx 10^(24)`B. `4.831 xx 10^(31)`C. `8.314 xx 10^(36)`D. `4.831 xx 10^(44)` |
Answer» Correct Answer - C `{:(E^(@)=(0.0591)/(2)logK,1.1 xx 2 = 0.06 log K),(36.22 = logK, 10^(36.22) = K_(f)),(8.314 xx 10^(36) =K,):}` |
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