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Using the expression `2d sin theta = lambda`, one calculates the values of `d` by measuring the corresponding angles `theta` in the range `0 to [email protected]`. The wavelength `lambda` is exactly known and error in `theta` is constant for all values of `theta`. As `theta` increases from `[email protected]`A. the absolute error in d remains constantB. the absolute error in d increaseC. the fractional error in d remains constantD. the fractional error in d decreases.

Answer» Correct Answer - D


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