1.

Using the Gibb's free energy change,DeltaG^(@) =+63.3kJ for the following reaction Ag_(2)CO_(3)(s)hArr2Ag^(+)(aq)+CO_(3)^(2-)(aq) the K_(sp) of Ag_(2)CO_(3) in water at 25^(@)C is (R=8.314 JK^(-1) "mol"^(-1))

Answer»

`3.2xx20^(-26)`
`8.0xx10^(-12)`
`2.9xx10^(-3)`
`7.9xx10^(-12)`

Solution :`Delta G^(@) = - 2.303 ` RT log `K_(SP)`
`63.3xx10^(3)J =- 2.303xx8.314xx298 logK_(sp)`
`=-5705. 84 log K_(sp)`
or log `K_(sp)=(63.3xx10^(3))/(57.5.84)=-11.09`
`:. K_(sp)=` ANTILOG `(bar(12).91)`
`=8.128xx10^(-12)`


Discussion

No Comment Found