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Using the ideal gas equation, determine the value of gas constant R. Given that one gram mole of a gas at S.T.P occupies a volume of 22.4 litres

Answer» Correct Answer - `8.31 J mole^(-1) K^(-1)`
Here, `R = ? V = 22.4` litre `= 22.4 xx 10^(3) m^(3)`
at S.T.P, `T =273 K`, and
`P=1` atmosphere `= 1.013 xx 10^(5)N//m^(2)`
For one mole of gas,
`PV =RT`
`R = (PV)/(T) = (1.013 xx 10^(5) xx 22.4 xx 10^(-3))/(273)`
`= 8.31 J mole^(-1) K^(-1)`.


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