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Using the ideal gas equation how will you calculate the values of R ? |
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Answer» Solution :We can calculate R using the equation, `R=(PV)/(nT)` (i) P is 1 atm, volume `22.414 md^(3)`. For 1 OLE at 273.15 K. `R=(1 atm xx22.414 md^(3))/(1 "mol"xx273.15 k)` `=0.0821 dm^(3) atm. "mol"^(-1)K^(-1)` (II) (STP), Where `P=1 "bar" (10^(5)` pascal) `V=22.71xx10^(-3)m^(3) ` for 1 mole of gas at `273.15K` `R=(10^(5)Px xx22.71xx10^(-3)m^(3))/(1 "mol"xx273.15K)` `=8.314 Pam^(3) K^(-1) "mol"^(-1)` `=8.314xx10^(-2) "bar" m^(3) K^(-1) "mol"^(-1)` `=8.314xx10^(-2) "bar" dm^(3)K^(-1) "mol"^(-1)` `=8.314xx10^(-2) bar LK^(-1)"mol"^(-1)` `=8.314 J K^(-1) "mol"^(-1)` |
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