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Using the information in the preceding problem, calculate the solubility product of `AgI` in water at `25^(@)C [E_((Ag +Ag)^(@) = +0.799volt]`:-A. `1.97 xx 10^(-17)`B. `7.91 xx 10^(-17)`C. `1.79 xx 10^(-17)`D. `9.17 xx 10^(-17)` |
Answer» Correct Answer - B `AgI+e^(-)rarr Ag+ I^(-) E^(@)= -0.151` `{:(E^(@)=-0.95 ,,,E=E^(@)-(0.0551)/(1)log K_(sp)),(-16.074=log_(10)K_(sp),,,10^(-16.074)=K_(sp)):}` `7.91xx10^(-17)=K_(sp)` |
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