Using the relation for potential energy of a current carrying planar loop in a uniform magnetic field, obtain expression for work done in moving the planar loop from its unstable equilibrium position to the stable position.

Using the relation for potential energy of a current carrying planar l

1.	Using the relation for potential energy of a current carrying planar loop in a uniform magnetic field, obtain expression for work done in moving the planar loop from its unstable equilibrium position to the stable position.
Answer» Potential energy of a current loop when its dipole moment `vecM` makes angle `theta` with the field `vecB` is given by `U=-MB cos theta` Work done in turning the loop from orientation `theta_1` to `theta_2` is `W=-MB(cos theta_2-cos theta_1)` In unstable equilibrium, `theta_1=180^@`, and in stable equilibrium `theta_2=0^@` `:. W=-MB(cos 0^@-cos 180^@)=-MB(1+1)` `=-2MB=-2(NIA)B`

Discussion

No Comment Found

Related InterviewSolutions

A current carrying loop consists of 3 identical quarter circles of radius R, lying in the positive quadrants of the x-y, y-z and z-x planes with their centres at the origin, joined together. Find the direction and magnitude to `vecB` at the origin.
A long straight wire carries a current of `2A`. An electron travels with a velocity of `4xx10^4ms^-1` parallel to the wire `0*1mm` from it, and in a direction opposite to the current. What force does the magnetic field of current exert on the moving electron. Charge on electron `=1*6xx10^(-19)C`.
The variation of magnetic susceptibility `chi` with the temperature T of a ferromagnetic material can be plotted asA. B. C. D.
A wire of length L metre carrying a current of I ampere is bent in the form of a circle. Find its magnetic moment.
A wire of length `L metre ` , carrying a current `I `ampere is bent in the form of a circle . The magnitude of its magnetic moment is …………. ` MKS units ` .A. `(IL)/(4pi)`B. `(IL^(2))/(4pi)`C. `(I^(2)L^(2))/(4pi)`D. `(I^(2)L)/(4pi)`
A wire of length `L metre ` , carrying a current `I `ampere is bent in the form of a circle . The magnitude of its magnetic moment is …………. ` MKS units ` .
A long wire carries a steady curent . It is bent into a circle of one turn and the magnetic field at the centre of the coil is `B`. It is then bent into a circular loop of `n` turns. The magnetic field at the centre of the coil will beA. nBB. `n^(2)B`C. 2nBD. `2n^(2)B`
A long solenoid has a radius `a` and number of turns per unit length is `n`. If it carries a current i, then the magnetic field on its axis is directly proportional toA. `ani`B. `ni`C. `(ni)/a`D. `n^(2)i`
Two concentric circular coils of ten turns each are situated in the same plane. Their radii are `20` and `40 cm` and they carry respectively `0.2` and `0.3` ampere current in opposite direction. The magnetic field in `Wb//m^(3)` at the centre isA. `35/4 mu_(0)`B. `(mu_(0))/80`C. `7/80 mu_(0)`D. `5/4 mu_(0)`
A particle of mass `m` and charge `q` moves with a constant velocity `v` along the positive `x` direction. It enters a region containing a uniform magnetic field `B` directed along the negative `z` direction, extending from `x = a` to `x = b`. The minimum value of `v` required so that the particle can just enter the region `x gt b` isA. `qb B//m`B. `q(b-a)B//m`C. `qa B//m`D. `a(b+a)B//2m`

Using the relation for potential energy of a current carrying planar loop in a uniform magnetic field, obtain expression for work done in moving the planar loop from its unstable equilibrium position to the stable position.

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment