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Using the valence bond approach, deduce the shape and magnetic behaviour of [Cr(NH_(3))_(6)]^(3+) ion. |
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Answer» Solution :Cr has electronic configuration [Ar] `4S^(1) 3d^(5)` `Cr^(3+)` has electronic configuration [Ar] `4s^(0) 3d^(3)` `d^(2)sp^(3)` HYBRIDISATION GIVES octahedral shape. The complex is PARAMAGNETIC due to presence of UNPAIRED electrons. |
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