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Using the valence bond approach, predict the shape and magnetic behaviour of [CoCl_(4)]^(2-). |
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Answer» Solution :Electronic configuration of CO : [Ar] `4s^(2)3D^(7)`. Electronic configuration of `Co^(2+) : [Ar] 4s^(0) 3d^(7)`. `Cl^(-)` does not cause pairing of electrons because it is weak field LIGAND. HENCE, It has tetrahedral shape and is paramagnetic due to presence of THREE unpaired electrons. |
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